8x^2=4800

Solution for 8x^2=4800 equation:

8x^2=4800

We move all terms to the left:

8x^2-(4800)=0

a = 8; b = 0; c = -4800;
Δ = b2-4ac
Δ = 02-4·8·(-4800)
Δ = 153600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{153600}=\sqrt{25600*6}=\sqrt{25600}*\sqrt{6}=160\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-160\sqrt{6}}{2*8}=\frac{0-160\sqrt{6}}{16}
=-\frac{160\sqrt{6}}{16}
=-10\sqrt{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+160\sqrt{6}}{2*8}=\frac{0+160\sqrt{6}}{16}
=\frac{160\sqrt{6}}{16}
=10\sqrt{6}
$